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  1. Prepare
  2. Linux Shell
  3. Bash
  4. Compute the Average
  5. Discussions

Compute the Average

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353 Discussions

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  • axelblazze
     + 0 comments

    Wrong Code uses integer arithmetic ($((sum + num))), which truncates floating-point numbers, leading to incorrect results when decimals are involved. For example, with inputs 1.5, 2.5, and 3.0, the sum becomes 6, resulting in an incorrect average of 2.000.

    Correct code uses bc for all arithmetic, which handles both integers and floating-point numbers correctly. With the same inputs, the sum becomes 7.0, and the correct average of 2.333 i

  • Chaitanyasharm14
     + 0 comments

    (easy solution is here : and if you are fail in one test and pass 5 test it is because you are not useing %0.3f .else use this bigner code. :) 

    read n
result=0
for((i=0;i<$n;i++))
do
    read num
    result=$(echo " $result + $num " |bc)
done
r=$(echo "$result / $n" | bc -l)
printf "%0.3f" "$r"

  • dhruvflare
     + 0 comments
    #!/bin/bash

read n
str="0"

# for i in {0..$n};
for ((i=0; i<$n; ++i));
do
    read a
    str="$str+$a"
done
echo "($str)/$n" | bc -l | xargs printf "%.3f"

  • juanlopezaranza1
     + 0 comments
    read N

sum=0

for((i=1; i<=N; i++))
do
    read X
    sum=$((sum+X))
done

expression="$sum / $N"

result=$(printf %.3f $(echo $expression|bc -l))

echo $result

  • mustafaalhnuty5
     + 1 comment
    read count_of_number
if [[ "$count_of_number" -ge 1 && "$count_of_number" -le 500 ]]; then
    list_of_integers=0
    for number in $(seq 1 $count_of_number)
        do
            read numbers
            if [[ "$numbers" -ge -10000 && "$numbers" -le 10000 ]]; then
            list_of_integers=$(($numbers + $list_of_integers))
            else
                echo "the number: $numbers is out of the range (-10000 <= x <= 10000)"
                exit 1
            fi
        done
    average=$(echo "scale=4; $list_of_integers / $count_of_number" | bc -l | xargs printf "%.3f")
    echo $average
else
    echo "the count of number is out of the range (1 <= N <= 500)"
fi