Arrays Introduction

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  • + 0 comments
    #include <cmath>
    #include <cstdio>
    #include <vector>
    #include <iostream>
    #include <algorithm>
    using namespace std;
    
    int main() {
        int n;
        cin>>n;
        vector <int> v(n);
        for (int i = 0; i < n; i++) {
            cin >> v[i];                // input elements
        }
        
        reverse(v.begin(),v.end());
        for (int i = 0; i < n; i++) {
            cout << v[i] << " ";
        }
        return 0;
    }
    
  • + 0 comments

    Here is my solution to this without using pointers:

    int main() {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT */ 
        int size;
        cin >> size;
        int nums[size];
        for (int i = size - 1; i >= 0; i--) {
            cin >> nums[i];
        }
        for (int j = 0; j < size; j++){
            cout << nums[j] << " ";
        }
        
         
        return 0;
    }
    
  • + 0 comments

    include iostream

    int main() { int n; std::cin>>n; const int SIZE = n; int numbers[SIZE];

    for (int i = 0; i < n; ++i) {
        std::cin >> numbers[i]; 
    }
    for (int i=0; i<n/2 ; ++i){
        int temp =numbers[i];
        numbers[i]=numbers[n-1-i];
        numbers[n-1-i]=temp;
    }
    for(int i= 0; i< n; ++i){
        std::cout<<numbers[i]<<" ";
    }
    
    
    return 0;
    

    }

  • + 0 comments

    include

    include

    include

    include

    include

    using namespace std;

    int main() { /* Enter your code here. Read input from STDIN. Print output to STDOUT */

      int n;
    
    cin >> n;
    
    int integers[n];
    
    for (int i = 0; i < n; i++) {
        cin >> integers[i];
    }
    // For Reverse Interger..
    for (int i = n-1; i >= 0; i--) {
        printf("%d ", integers[i]);
    }
    
    return 0;
    

    }

  • + 0 comments
    #include <iostream>
    using namespace std;
    
    
    int main() {
        int N;
        cin >> N;
        int num[N];
        for (int i = 0; i < N; i++)
        {
            cin >> num[i];
        }
        
        for (int i = N - 1; i >= 0; i--) 
        {
            cout << num[i] << " ";
        }
        
        return 0;
    }