Java Solution:

ArrayList list =new ArrayList<>(a);

Collections.reverse(list);

return list;

int[] arr = a.ToArray(); Array.Reverse(arr); return arr.ToList(); this worked but i don't understand why this did not Array.Reverse(a.ToArray); return a.ToList();

please help me to correct the code

include

int main() { int a[150], temp , size, i; printf("Enter the size of the array : "); scanf("%d", &size); for (i = 0; i < size; i++) { printf("Enter element number %d :", i + 1); scanf("%d", &a[i]); } printf("your array elements are :"); for (i = 0; i < size; i++) { printf("%d", a[i]); }

printf("\nreverse array : ");
for (i = 0; i < size/2; i++)
{
    temp = a[i];
    a[i] = a[size - i - 1];
    a[size - i - 1] = temp;
}
for (i = 0; i < size; i++)
{
    printf("%d", a[i]);
}

}

public static List reverseArray(List a) { ArrayList list=new ArrayList<>(a); Collections.reverse(list); return list; }

**JavaScript------* Stack----

function reverseArray(a) {
    // Write your code here
    
      const stack = []

    for (let i=0; i<a.length; i++){

        stack.push(a[i])
        // console.log(stack)
    }


    let rev = []

    for(let i=0; i< a.length; i++){


        rev.push(stack.pop())

        // stack.pop()
        // rev.push(stack.pop())
    
        console.log(rev)

    }

    // console.log(stack)
    return rev

}