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  1. Prepare
  2. Data Structures
  3. Arrays
  4. Left Rotation
  5. Discussions

Left Rotation

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3528 Discussions

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  • mutassimalzeem
     + 0 comments

    I have got a very short and efficient code for this. I used Python

    def rotateLeft(d, arr): # Efficient left rotation using slicing return arr[d:] + arr[:d]

  • shaikabubakr133
     + 0 comments

    public static void reverse(List arr1) { int left = 0, right = arr1.size() - 1; while (left < right) { int l = arr1.get(left); int r = arr1.get(right); arr1.set(left, r); arr1.set(right, l); left++; right--; } }

    public static List<Integer> rotateLeft(int d, List<Integer> arr) {
    d = d % arr.size();
    if (d == 0)
        return arr;
    else {
        List<Integer> l1 = new ArrayList<>(arr.subList(0, d));
        List<Integer> l2 = new ArrayList<>(arr.subList(d, arr.size()));
        reverse(l1);
        reverse(l2);
        l1.addAll(l2);
        reverse(l1);
        return l1;
    }
}

  • melodicodyssey84
     + 0 comments
    function rotateLeft(d: number, arr: number[]): number[] {
    // Write your code here
    /**
     * Well, we could rotate the array `d` number of times,
     * but that seems like wasteful action.
     * 
     * Better to slice the array and move the chunk
     */
    const left: number[] = arr.slice(0, d);
    const right: number[] = arr.slice(d, arr.length);
    return right.concat(left);}
}

  • zahra_khan1313
     + 0 comments

    def rotateLeft(d, arr): for i in range(d): arr.append(arr.pop(0)) return arr

  • wendllandmkl
     + 0 comments

    Hey everyone, I was working through the Left Rotation problem, and I found it to be a great exercise for understanding array manipulation. If you're interested in checking out more tools related to data and statistics, I recently came across a cool website that offers a Name Popularity Checker. It's a handy resource to check how popular a name has been over time. Might be fun to try out if you're interested in names and trends!