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Can anyone help me what is wrong with below code? For this particular problem, there could be multiple solutions.
void aOrB(int k, char* a, char* b, char* c) {
long long num_a, num_b, num_c;
//printf("sizeof num_a = %d \n",sizeof(num_a));
num_a = my_atoi(a);
num_b = my_atoi(b);
num_c = my_atoi(c);
/printf("a:%s -->%ld ",a,num_a);
printf("b:%s -->0x%x ",b,num_b);
printf("c:%s -->0x%x \n",c,num_c);/
// First clear the bits from value a
num_a &= num_c;
// Clear the bits from value b
num_b &= num_c;
// Now first OR a and b, then find how many bits
// temp is short off and it's bit position.
long long temp = num_a | num_b;
temp ^= num_c;
num_a |= temp;
if ((num_a | num_b) == num_c)
printf("num_a: 0x%x | num_b:0x%x = 0x%x\n",num_a, num_b, num_c);
int count = (countOne(my_atoi(a)^num_a)) + (countOne(my_atoi(b)^num_b));
if ( count > k)
printf("-1");
else {
printf("%ld \n",num_a);
printf("%ld \n",num_b);
}
printf("\n-------\n");
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A or B
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Can anyone help me what is wrong with below code? For this particular problem, there could be multiple solutions. void aOrB(int k, char* a, char* b, char* c) { long long num_a, num_b, num_c; //printf("sizeof num_a = %d \n",sizeof(num_a)); num_a = my_atoi(a); num_b = my_atoi(b); num_c = my_atoi(c); /printf("a:%s -->%ld ",a,num_a); printf("b:%s -->0x%x ",b,num_b); printf("c:%s -->0x%x \n",c,num_c);/