Python3

def gamingArray(arr):
    # Write your code here
    helper = sorted(arr, reverse=True)
    d = dict()
    for i in range(len(arr)):
        d[arr[i]] = i
    count = 0
    n = len(arr) - 1
    for maxVal in helper:
        if d[maxVal] <= n:
            n = d[maxVal] - 1
            count += 1
        if n < 0:
            break
    return 'BOB' if count % 2 == 1 else 'ANDY'

public static String gamingArray(List<Integer> arr) {
// Write your code here

    int count = 0, end = -1;

    for(int i = 0; i< arr.size(); i++){

            count++;
            end = arr.indexOf(Collections.max(arr));
            //System.out.println("MAX: "+ Collections.max(arr) +" Ind: "+end);

            for(int j = end; j< arr.size(); j++){
                //System.out.println("J: "+j+" Remove: "+ arr.get(j));
                arr.remove(j);
                j--;
        }

        // for(Integer k:arr){
        //     System.out.println("Arr: "+k);
        // }
    }


            I dont know why all my test cases were not getting successful. Could any one help me with my solution and clearly explain how to work with constrains 

    if(count%2==0)    return "ANDY";
    else    return "BOB";

}

python3 def gamingArray(arr): curr_max = 0 bob_turn = True for n in arr: if n > curr_max: curr_max = n bob_turn = not bob_turn return ['ANDY', 'BOB'][not bob_turn] `

what is the issue in my code I am getting time limit exceed.

def gamingArray(arr): count =0 arrlen = len(arr) for i in range(arrlen): if len(arr)>0: idx=arr.index(max(arr)) arr=arr[:idx] count+=1 winner = "ANDY" if count % 2 == 0 else "BOB" return winner

Thanks