Sort by

recency

|

124 Discussions

|

  • + 0 comments

    perl

    while(<>){
        chomp;
        next if $. == 1;
        /^[_\.]\d+[a-zA-Z]*_?$/ ? print "VALID\n" : print "INVALID\n";
    
  • + 0 comments

    Java 15

    import java.io.*;
    import java.util.*;
    import java.util.regex.Pattern;
    import java.util.regex.Matcher;
    public class Solution {
        public static void main(String[] args) {
            Scanner scanner = new Scanner(System.in);
            int n=Integer.parseInt(scanner.nextLine());
            Pattern pattern = Pattern.compile("^[_\\.]\\d+[a-zA-Z]*_?$");
            for(int i=0;i<n;i++)
            {   Matcher matcher = pattern.matcher(scanner.nextLine());
                if (matcher.find()) System.out.println("VALID");
                else    System.out.println("INVALID");
            }
        }
    }
    
  • + 0 comments

    vau!

    import re
    
    regex = re.compile(r'^[_\.]\d+[a-zA-Z]*_?$')
    
    n = int(input())
    for _ in range(n):
        print('VALID' if regex.match(input()) else 'INVALID')
    
  • + 0 comments

    here is my reg expression

    import re
    pattern = "^((_|\.)[0-9]+[a-zA-Z]*_?)$"
    
    for _ in range(int(input())) :
        string = input()
        if re.search(pattern ,string) :
            print("VALID")
        else:
            print("INVALID")
    
  • + 0 comments
    import re
    for _ in range(int(input())):
        regex = re.compile(r"[_.]\d+[a-zA-Z]*_?$")
        print("VALID" if regex.match(input()) else "INVALID")