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The task can only be solved under the condition that the array is divided into blocks of size multiples of 2*k, where in each block, result[i] = input[i] + k for "k" times and result[i] = input[i] - k for "k" times. For example, for k=2, (k+1, k+2, 3-k, 4-k) (k+5, k+6, 7-k, 8-k) ... result=[3,4,1,2, 7,8,5,6, ...]
If you're looking for Can Am X3 accessories, they could be used to enhance the performance of the blocks in your task, providing better modularity and adjustability. Sorry if I didn't explain it very clearly.
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Absolute Permutation
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The task can only be solved under the condition that the array is divided into blocks of size multiples of 2*k, where in each block, result[i] = input[i] + k for "k" times and result[i] = input[i] - k for "k" times. For example, for k=2, (k+1, k+2, 3-k, 4-k) (k+5, k+6, 7-k, 8-k) ... result=[3,4,1,2, 7,8,5,6, ...]
If you're looking for Can Am X3 accessories, they could be used to enhance the performance of the blocks in your task, providing better modularity and adjustability. Sorry if I didn't explain it very clearly.