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  1. Prepare
  2. Algorithms
  3. Implementation
  4. 3D Surface Area
  5. Discussions

3D Surface Area

  • heshansulakshan1
     + 0 comments

    So here is my code.For an help for you guys just look at the object from front back right left top bottom and you will notice that each of those pairs are equal.Also see the list A and try to get the pattern.Then the coding is simple

    #!/bin/python3

import math
import os
import os

def surfaceArea(A):
    D = []
    for a in A:
        S = []
        for i in range(1, W):
            S.append(abs(a[i] - a[i - 1])) 
        D.append(sum(S) + a[-1] + a[0])

    E = []
    for d in range(H - 1): 
        for c in range(W):  
            E.append(abs(A[d][c] - A[d + 1][c]))

    E.append(sum(A[0]) + sum(A[-1]))  
    return sum(D) + sum(E) + 2 * H * W 

if __name__ == '__main__':
    fptr = open(os.environ['OUTPUT_PATH'], 'w')

    first_multiple_input = input().rstrip().split()

    H = int(first_multiple_input[0])
    W = int(first_multiple_input[1])

    A = []
    for _ in range(H):
        A.append(list(map(int, input().rstrip().split())))

    result = surfaceArea(A)

    fptr.write(str(result) + '\n')
    fptr.close()

    print(A)