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  1. Prepare
  2. Tutorials
  3. 30 Days of Code
  4. Day 6: Let's Review
  5. Discussions

Day 6: Let's Review

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recency

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3399 Discussions

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  • temizogluakadir
     + 0 comments

    n=int(input())

    def bunedir(word_list : list) : for word in word_list : 

        evens = "" 
    odds = ""

    for idx , val in enumerate(word):
        if idx % 2 == 0 :
            evens += val
        else :
            odds += val

    print(f"{evens} {odds}")

    for _ in range(n): word_list = list(input().splitlines()) bunedir(word_list)

  • luca_h94
     + 0 comments
    N = int(input())

def reorder_string(my_string):
    l_my_string = list(my_string)
    even_string = "".join([l_my_string[i*2] for i in range(0,(len(my_string)+1)//2)])
    uneven_string = "".join([l_my_string[1+(i*2)] for i in range(0,len(my_string)//2)])
    print(even_string, uneven_string)


for _ in range(0,N):
    reorder_string(input())

  • rohitshivdhaniy2
     + 0 comments

    const strsplit = input.split("\n").slice(1); Day 6 lets Review in JavaScript 

    for(let str of strsplit){
    let even = "";
    let odd = "";
   for(i=0; i<str.length; i++){
       if(i% 2 ==0){
           even+= str[i]
       }else{
           odd+= str[i]
       }
   }
   console.log(``${even} $`{odd}`)

}

  • adadasaivenkat01
     + 0 comments
    # Enter your code here. Read input from STDIN. Print output to STDOUT
n=int(input())
for i in range(n):
    l=list(input())
    for j in range(len(l)):
        if j%2==0:
            print(l[j],end="")
    print(end=" ")
    for k in range(len(l)):
        if k%2!=0:
            print(l[k],end="")
    print()

  • deekshithakandr1
     + 0 comments

    def string(s): even_char = s[::2] odd_char = s[1::2] return f"{even_char} {odd_char}" t = int(input()) for i in range(t): s = input() print(string(s))