We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Tutorials
  3. 30 Days of Code
  4. Day 9: Recursion 3
  5. Discussions

Day 9: Recursion 3

  • jonlle19
     + 0 comments

    My solution with JavaScript:

    // Base case at 2 to avoid redundancy: multiplying by 1 does not change the result.
function factorial(n) {
    if(n > 2) {
        return n * factorial(n-1);
    } else {
        return 2;
    }
}