#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>


//----------------------------------------------------------------------------------------------

/*!
 * @brief given a date in yyyymmdd format, returns the number of days elapsed since 01-01-01 CE
 * @note assumes gregorian, no error checking is done since valid dates guaranteed by problem statement
 */
unsigned long days_since_bce(int num_years, int num_months, int num_days)
{
    unsigned long accum    =    0;
    
    //------------- year handling ---------------------------------------
    // days in normal years
    accum += num_years * 365;
    
    // days in leap years
    accum += (num_years / 4) - (num_years / 100) + (num_years / 400);
    
    //------------- month handling --------------------------------------
    // add the number of days of the _previous_ months
    // fallthroughs are intentional
    switch (num_months)
    {
        case 12:    accum += 30; 
        case 11:    accum += 31; 
        case 10:    accum += 30; 
        case 9:     accum += 31; 
        case 8:     accum += 31; 
        case 7:     accum += 30; 
        case 6:     accum += 31; 
        case 5:     accum += 30; 
        case 4:     accum += 31; 
        case 3:     accum += 28; 
        case 2:     accum += 31; 
    }
    
    //------------- day handling --------------------------------------
    accum += num_days;
    
    //------------- done ----------------------------------------------
    return accum;
}


//----------------------------------------------------------------------------------------------

int main() {
    int y_returned;
    int m_returned;
    int d_returned;

    scanf("%d %d %d", &d_returned, &m_returned, &y_returned);
    unsigned long return_date = days_since_bce(y_returned, m_returned, d_returned);

    int y_due;
    int m_due;
    int d_due;

    scanf("%d %d %d", &d_due, &m_due, &y_due);
    unsigned long due_date = days_since_bce(y_due, m_due, d_due);
    
    long fine = (return_date - due_date)*15L;
    
    // returned early ?
    if (fine < 0) fine = 0;
    
    // returned after a year boundary ?
    if (y_returned > y_due) fine = 10000;
    
    // returned after a month boundary ?
    if (y_returned == y_due)
    {
        if (m_returned > m_due) fine = (500 * (m_returned - m_due));
    }
    
    // all done
    printf("%ld", fine );

    return 0;
}