Here's the ugly Typescript that doesn't use conditionals, lol.

function fail() {
    throw new Error("Not an int")
}

function main() {
    const S: string = readLine();
    try {
        const num = Number(S)
        const test = !Number.isInteger(num) && fail()
        console.log(num)
    } catch (e) {
        console.log("Bad String")
    }
}

I don't think you can actually complete this task using Typescript as the resulting number is just NaN and throwing your own error will fail becasue you have an if statement.

Hey, Here is my code : " if name == 'main': a = input() try: print(int(a)) except Exception: print('Bad String') " and the rerult is: "Error reading result file.You should use exception handling concepts."

help me please :)

import Foundation

/* * Define an ErrorType */ enum StringToIntTypecastingError: Error { case BadString }

func stringToInt(inputString: String) throws -> Int {
    guard let int = Int(inputString) else {
        throw StringToIntTypecastingError.BadString
    }
    return int
}

/* * Read the input */ let inputString = readLine()!

do { try print(stringToInt(inputString: inputString)) } catch StringToIntTypecastingError.BadString { print("Bad String") }

**// I am getting Error reading result file.You should use exception handling concepts.

but output printing correct can any one please help in this in Swift language **