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  1. Prepare
  2. Tutorials
  3. 30 Days of Code
  4. Day 8: Dictionaries and Maps
  5. Discussions

Day 8: Dictionaries and Maps

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2708 Discussions

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  • mirovlab
     + 0 comments

    Be Aware: After the n lines of phone book entries, there are an unknown number of lines of queries.

    One of solutions: while True: try: ... except EOFError: ...

  • urbanoyaan
     + 0 comments

    This is my submission in JS

    let list = input.split('\n');
    let phoneBook = {};
    const n = parseInt(list[0]);


    for (let i = 1; i <= n; i++) {
        let [name, number] = list[i].split(' ');
        phoneBook[name] = number;
    }

    for (let i = n + 1; i < list.length; i++) {
        let name = list[i];
        if (name in phoneBook) {
            console.log(`${name}=${phoneBook[name]}`);
        } else {
            console.log('Not found');
        }
*     }

  • mujahed_issa2004
     + 0 comments

    im failing in test case1 but passing all the other ones im about to loose it

  • adadasaivenkat01
     + 1 comment
    # Enter your code here. Read input from STDIN. Print output to STDOUT
n=int(input())
k={}
for i in range(n):
    name,ph=input().split()
    k[name]=int(ph)
try:
    while True:
        inp=input()
        if inp in k:
            print(f'{inp}={k[inp]}')
        else:
            print('Not found')
except EOFError:
    pass

  • deekshithakandr1
     + 0 comments

    Enter your code here. Read input from STDIN. Print output to STDOUT

    n = int(input()) phone_book = {} for _ in range(n): entry = input().split() name = entry[0] phone_number = entry[1] phone_book[name]=phone_number try: while True: query = input() if query in phone_book: print(f"{query}={phone_book[query]}") else: print("Not found") except EOFError: pass