Use an uppercase N

n=int(input("enter the no.")) if((2<=n<=5)%2==0): print(n) else: print("wrong no")

HI, friends, I got an error on this code that I want the values from 2 to 5 but I found that this statement always gave a true and display the output any friend can explain why this is happening

For Csharp:

if (N % 2 != 0) // If N is odd

    {

        Console.WriteLine("Weird");
    }

    else // If N is even

    {

        if (N >= 2 && N <= 5)
        {

            Console.WriteLine("Not Weird");
        }
        else if (N >= 6 && N <= 20)
        {

            Console.WriteLine("Weird");

        }

        else // N > 20
        {

            Console.WriteLine("Not Weird");
        }
    }
}

} Console.WriteLine("Weird"); }}}

solved in java!

    if(N%2==0)
    {
        if  ((2<=N && N<=5)|| N>20)
    {
        System.out.println("Not Weird");
    }
    else if (6<=N && N<=20)
    {
        System.out.println("Weird");
    }
    }
    else
    {
        System.out.println("Weird");
    }

function main() { const N = parseInt(readLine().trim(), 10); let result = "Weird";

if (N % 2 != 0) {
    result = "Weird";        
}else if ( N >=2 && N <= 5) {
    result = "Not Weird"; 
}else if (N >= 6 && N <= 20 ) {
    result = "Weird"; 
}else {
    result = "Not Weird"; }

console.log(result);

}