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  1. Prepare
  2. Tutorials
  3. 30 Days of Code
  4. Day 22: Binary Search Trees
  5. Discussions

Day 22: Binary Search Trees

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recency

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489 Discussions

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  • willlltrue
     + 0 comments

    Javascript code:

    // Start of function getHeight
this.getHeight = function(root) {

    if (root===null) return -1;
    leftheight=this.getHeight(root.left);
    rightheight=this.getHeight(root.right);
    return Math.max(leftheight,rightheight)+1;

}; // End of function getHeight

    Don't understand how the output get 2 with the below input. Any expert can help to shed some light please. Thanks!

    9 20 50 35 44 9 15 62 11 13

  • jaykipkerich
     + 0 comments

    Python 3 solution

    python def getHeight(self,root):

        if root.left:
        left = self.getHeight(root.left) + 1
    else:
        left = 0
    if root.right:
        right =self.getHeight(root.right) +1
    else:
        right = 0

    return max(left, right)

  • syed_imraan92
     + 0 comments
    c# csharp

solution that doesn't use recursion

private static int getHeight(Node root)
{
    if (root == null)
    {
        return -1; // height of empty tree is -1
    }

    Queue<Node> queue = new Queue<Node>();
    queue.Enqueue(root);
    int height = -1;

    while (queue.Count > 0)
    {
        int nodeCount = queue.Count;  // Number of nodes at the current level
        height++;

        // Process each node at the current level
        while (nodeCount > 0)
        {
            Node node = queue.Dequeue();

            // Enqueue left and right children of the current node
            if (node.left != null)
            {
                queue.Enqueue(node.left);
            }
            if (node.right != null)
            {
                queue.Enqueue(node.right);
            }

            nodeCount--;
        }
    }

    return height;
}

  • mrkobel
     + 0 comments

    This is what I came up with:

        def getHeight(self,root):
        if root is None:
            return -1
        else:
            return max(self.getHeight(root.left),self.getHeight(root.right)) + 1

  • alfonso_munozpo2
     + 0 comments

    Using Python 3’s pattern-matching:

    def getHeight(self, root):
    match root:
        case Node(left=None, right=None):
            return 0
        case Node(left=None):
            return 1 + self.getHeight(root.right)
        case Node(right=None):
            return 1 + self.getHeight(root.left)
        case _:
            return max(1 + self.getHeight(root.left), 1 + self.getHeight(root.right))

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