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  1. Prepare
  2. Tutorials
  3. 30 Days of Code
  4. Day 10: Binary Numbers
  5. Discussions

Day 10: Binary Numbers

  • pureheroine
     + 0 comments

    here's my c++ solution

        do {
        current = n & 1 ? current + 1 : 0;
        max = current > max ? current : max;
    } while (n >>= 1);