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Java solution:
... int maxSum = Integer.MIN_VALUE; for (int i = 0; i <= arr.size() - 3; i++) { for (int j = 0; j <= arr.size() - 3; j++) { int currentSum = calcSum(i, j, arr); if (currentSum > maxSum) { maxSum = currentSum; } } } ... private static int calcSum(int vEdge, int hEdge, List<List<Integer>> arr) { int[][] hourGlassCooridnates = {{0, 0}, {0, 1}, {0, 2}, {1, 1}, {2, 0}, {2, 1}, {2, 2}}; int sum = 0; for (int[] coordinate : hourGlassCooridnates) { int i = coordinate[0]; int j = coordinate[1]; sum += arr.get(vEdge + i).get(hEdge + j); } return sum; }
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Day 11: 2D Arrays
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Java solution: