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Time complexity: O(n^2) Space complexity: O(1)
Of course, one can assign the coordination of the 2-D array to compute hourglasses value directly.
int compute_hourglasses(int** arr, int start_row, int start_cloumn){ int sum = 0; for (int i = start_row-1; i<=start_row+1; i++){ for (int j = start_cloumn-1; j <= start_cloumn+1; j++){ sum += arr[i][j]; } } sum -= (arr[start_row][start_cloumn-1] + arr[start_row][start_cloumn+1]); return sum; } int hourglassSum(int arr_rows, int arr_columns, int** arr) { int start_row = 1, start_cloumn = 1; int end_row = arr_rows-1, end_column = arr_columns-1; int max_res = compute_hourglasses(arr, start_row, start_cloumn); for (int i = start_row; i<end_row; i++){ for (int j = start_cloumn; j< end_column; j++){ int temp = compute_hourglasses(arr, i, j); if (temp > max_res) max_res = temp; } } return max_res; }
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2D Array - DS
You are viewing a single comment's thread. Return to all comments →
Time complexity: O(n^2) Space complexity: O(1)
Of course, one can assign the coordination of the 2-D array to compute hourglasses value directly.