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  1. Prepare
  2. C
  3. Arrays and Strings
  4. 1D Arrays in C
  5. Discussions

1D Arrays in C

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484 Discussions

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  • fluenoriph
     + 0 comments

    int main() { int n; scanf("%d", &n);

    const unsigned int SIZE = n;
int* p = malloc(SIZE * sizeof(int));
if (!p) { exit(1); }

int sum = 0;

for (int i = 0; i < SIZE; ++i) {
    scanf("%d", p + i);
    sum += p[i];
}
printf("%d\n", sum);

free(p);
p = NULL;

return 0;

    }

  • prasannkumar2k91
     + 0 comments

    int n;

    scanf("%d",&n);

n++;

int* arr=(int*)malloc(n * sizeof(int));

arr[0]=0;

for(int i=1; i<n; i++){
scanf("%d",arr+i);
arr[0]+=arr[i];
if(i==n-1)
printf("%d",arr[0]);
}
free(arr);

  • abhiroop2021
     + 0 comments

    How can we take those 'n' inputs using spaces in between them as shown in the sample input?

  • sezzaldiin0
     + 1 comment
    #include <stdio.h>
#include <stdlib.h>

int main() 
{
    int n;
    scanf("%d", &n);

    // Create a dynamic array of size n
    int* arr = (int*)malloc(n * sizeof(int));

    // Read the values from stdin and store them in the array
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    // Calculate the sum of all elements in the array
    int sum = 0;
    for (int i = 0; i < n; i++) {
        sum += arr[i];
    }

    // Print the sum
    printf("%d\n", sum);

    // Free the memory where the array is stored
    free(arr);

    return 0;
}

  • ajayarun7899
     + 0 comments
    #include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
    int a,b[1000],sum=0;
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */    
   scanf("%d",&a);
    for(int i=0;i<a;i++)
    {
        scanf("%d", &b[i]); 
        sum+=b[i];
    }
    printf("%d",sum);
    return 0;
}