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with cte as ( select submission_date,hacker_id,count(*) as day_cnt from Submissions group by submission_date,hacker_id ), cte2 as ( select submission_date,hacker_id,count(hacker_id) over (partition by hacker_id order by submission_date asc rows between unbounded preceding and current row) cnt, datediff(day,'2016-02-29',submission_date) diff from cte ), first_part as ( select submission_date,count(hacker_id) cnt_dis from cte2 where cnt = diff group by submission_date ), cte3 as ( select submission_date,c.hacker_id,day_cnt,name,row_number() over (partition by submission_date order by day_cnt desc, c.hacker_id asc ) rw_num from cte c join Hackers h on c.hacker_id = h.hacker_id ) select f.submission_date,f.cnt_dis,c.hacker_id,c.name from first_part f join cte3 c on f.submission_date = c.submission_date where rw_num = 1 order by submission_date``
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15 Days of Learning SQL
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