#include using namespace std; long long fir[1000001]; void pre() { fir[1] = 1; long long po = 2; for(int i=2;i<=1000001;i++) { fir[i] = fir[i-1] + po; po+=2; } } long long sumOfGroup(long long k) { // Return the sum of the elements of the k'th group. long long ans = k*(fir[k] + fir[k+1]-2) /2; return ans; } int main() { pre(); long long k; cin >> k; long long answer = sumOfGroup(k); cout << answer << endl; return 0; }