#include using namespace std; long sumOfGroup(long k) { long before = ((1 + (k - 1))*(k-1))/2; long first = before * 2 + 1; long sum = ((first + (first + 2 * (k - 1)))*k)/2; return sum; } int main() { int k; cin >> k; long answer = sumOfGroup(k); cout << answer << endl; return 0; }