#include typedef long long ll; using namespace std; string canConstruct(vector a) { // Return "Yes" or "No" denoting whether you can construct the required number. vector ::iterator it; ll sum=0; int digit; for(it=a.begin();it!=a.end();++it) { ll no=*it; while(no!=0) { digit=no%10; no=no/10; sum=sum+digit; } } if(sum%3==0) return "Yes"; else return "No"; } int main() { int t; cin >> t; for(int a0 = 0; a0 < t; a0++){ int n; cin >> n; vector a(n); for(int a_i = 0; a_i < n; a_i++){ cin >> a[a_i]; } string result = canConstruct(a); cout << result << endl; } return 0; }