import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    static String canConstruct(int[] a) {
        // Return "Yes" or "No" denoting whether you can construct the required number.
          // Return "Yes" or "No" denoting whether you can construct the required number.
        int counter = a[0];
        int index = 1;
        int num = a[index];
        
        for(int i = 0; i< num; i++){
               int temp = 0;

            if(num > 1){   //we have more than one number to interpret
                Scanner scanner = new Scanner(System.in);
                List<Integer> list = new ArrayList<Integer>();
                while (scanner.hasNextInt())
                 temp += scanner.nextInt();
                }
                if(temp % 3 == 0){
                    return "Yes";
                }else
                    return "No";
            }
            // now it's only one number
            if(a[1] % 3 == 0){
                return "Yes";
            }
                return "No";
        }
    

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int t = in.nextInt();
        for(int a0 = 0; a0 < t; a0++){
            int n = in.nextInt();
            int[] a = new int[n];
            for(int a_i = 0; a_i < n; a_i++){
                a[a_i] = in.nextInt();
            }
            String result = canConstruct(a);
            System.out.println(result);
        }
        in.close();
    }
}