#!/bin/python

import sys
from itertools import permutations

def canConstruct(a):
    # Return "Yes" or "No" denoting whether you can construct the required number.
    numbers = map(int, [''.join(p) for p in permutations(a)])
    for n in numbers:
        if n % 3 == 0:
            return 'Yes'
    return 'No'
    

if __name__ == "__main__":
    t = int(raw_input().strip())
    for a0 in xrange(t):
        n = int(raw_input().strip())
        a = raw_input().replace(' ', '')
        result = canConstruct(a)
        print result