#!/bin/python3
from itertools import permutations
import sys

def canConstruct(a):
    # Return "Yes" or "No" denoting whether you can construct the required number.
    #print(a)
    s=""
    for i in a:
        s+=str(i)
    perms = [''.join(p) for p in permutations(s)]
    for i in perms:
        if(int(i)%3==0):
            return 'Yes'
    return 'No'
    

if __name__ == "__main__":
    t = int(input().strip())
    for a0 in range(t):
        n = int(input().strip())
        a = list(map(int, input().strip().split(' ')))
        result = canConstruct(a)
        print(result)