#include #define forn(i,a,b) for(int i = a; i < b; i++) using namespace std; long long dig(int n) { long long sum = 0; while(n != 0) { sum += n%10; n /= 10; } return sum; } string canConstruct(vector a) { // Return "Yes" or "No" denoting whether you can construct the required number. int n = a.size(); int sum = 0; forn(i,0,n) { sum += dig(a[i])%3; } sum %= 3; if(sum == 0) return "Yes"; else return "No"; } int main() { int t; cin >> t; for(int a0 = 0; a0 < t; a0++){ int n; cin >> n; vector a(n); for(int a_i = 0; a_i < n; a_i++){ cin >> a[a_i]; } string result = canConstruct(a); cout << result << endl; } return 0; }