#!/bin/python

import sys
from itertools import permutations

def canConstruct(a):
    # Return "Yes" or "No" denoting whether you can construct the required number.
    b = map(str, a);
    for p in permutations(b):
        num = int(''.join(p))
        if num%3==0:
            return True
    return False

if __name__ == "__main__":
    t = int(raw_input().strip())
    for a0 in xrange(t):
        n = int(raw_input().strip())
        a = map(int, raw_input().strip().split(' '))
        result = canConstruct(a)
        if result == True:
            print 'Yes'
        else:
            print 'No'