#!/bin/python3

import sys,itertools

def canConstruct(a):
    # Return "Yes" or "No" denoting whether you can construct the required number.
    v = list(itertools.permutations(a))
    f = False
    for item in v:
        if not int("".join([str(g) for g in item])) % 3:
            return "Yes"
            f = True
            break
        
    if not f:
        return "No"
        

if __name__ == "__main__":
    t = int(input().strip())
    for a0 in range(t):
        n = int(input().strip())
        a = list(map(int, input().strip().split(' ')))
        result = canConstruct(a)
        print(result)