- Prepare
- Interview Preparation Kit
- Recursive Digit Sum
Recursive Digit Sum
Recursive Digit Sum
We define super digit of an integer using the following rules:
Given an integer, we need to find the super digit of the integer.
- If has only digit, then its super digit is .
- Otherwise, the super digit of is equal to the super digit of the sum of the digits of .
For example, the super digit of will be calculated as:
super_digit(9875) 9+8+7+5 = 29
super_digit(29) 2 + 9 = 11
super_digit(11) 1 + 1 = 2
super_digit(2) = 2
Example
The number is created by concatenating the string times so the initial .
superDigit(p) = superDigit(9875987598759875)
9+8+7+5+9+8+7+5+9+8+7+5+9+8+7+5 = 116
superDigit(p) = superDigit(116)
1+1+6 = 8
superDigit(p) = superDigit(8)
All of the digits of sum to . The digits of sum to . is only one digit, so it is the super digit.
Function Description
Complete the function superDigit in the editor below. It must return the calculated super digit as an integer.
superDigit has the following parameter(s):
- string n: a string representation of an integer
- int k: the times to concatenate to make
Returns
- int: the super digit of repeated times
Input Format
The first line contains two space separated integers, and .
Constraints
Sample Input 0
148 3
Sample Output 0
3
Explanation 0
Here and , so .
super_digit(P) = super_digit(148148148)
= super_digit(1+4+8+1+4+8+1+4+8)
= super_digit(39)
= super_digit(3+9)
= super_digit(12)
= super_digit(1+2)
= super_digit(3)
= 3
Sample Input 1
9875 4
Sample Output 1
8
Sample Input 2
123 3
Sample Output 2
9
Explanation 2
Here and , so .
super_digit(P) = super_digit(123123123)
= super_digit(1+2+3+1+2+3+1+2+3)
= super_digit(18)
= super_digit(1+8)
= super_digit(9)
= 9